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Mathematics
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Calculus 2 - Integrals
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If we assume this is an even function, that is the function is symmetric about the y-axis, then the area under the curve between -1 and +1 (A) is twice the area under the curve between 0 and 1 (or A/2).
ok, i think i understand that
\[\int\limits_{0}^{3}f(x)dx = \int\limits_{0}^{1}f(x)dx + \int\limits_{1}^{3}f(x)dx = \frac{1}{2}\int\limits_{-1}^{1}f(x)dx + \int\limits_{1}^{3}f(x)dx =\\\frac{A}{2} + B\]
plug in A and b?
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They have not provided the values of A and B. they say they just want the answers in terms of A and B. So it is A/2 + B.
Nvm, sorry. I mistyped it in. thanks
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