Question

given a parallelogram ABCD (diagonals from A to C and D to B. where the diagonals cross is E.), find the following: AE= 3x+2y EC= 25 AB= 2x+9y Cd= 5x+y-5. how do i find x and y

Answer 1

In a parallelogram:
the opposite sides are of equal length. Therefore, 2x+9y = 5x+y-5
the diagonals bisect each other. Therefore, AE = EC or 3x+2y = 25.

You have two equations and two unknowns. So you can solve for x and y.

Answer 2

every time i work out that problem it never equals out. help.

Answer 3

2x+9y = 5x+y-5
5x + y - 5 - 2x - 9y = 0
3x - 8y = 5 ----- (1)
3x + 2y = 25 ------ (2)
subtract (1) from (2)
10y = 20
y = 2.
put y = 2 in (2)
3x + (2)(2) = 25
3x + 4 = 25
3x = 21
x = 7

x = 7; y = 2.

Answer 4

also for that same picture but for these DF=2x=y CF=15 AB=3x+2y DA=5x-3y+3 (f is where the diagonals cross.)

Answer 5

Are you sure the vertices have the letters A,B,C,D counter-clockwise? If not, you can click on the Draw button below the reply box and draw and label the diagram.

Answer 6

no it is ABCD starting at the left top corner for this one.

Answer 7

You are given two adjacent sides of the parallelogram as (3x+2y) and (5x+3y+3)?
And one half of each diagonal as (2x+y) and 15?

Answer 8

It would make the question easier to understand if you'd draw it, label the vertices and write down the length of each segment near it.

Answer 9

You can also take a pic of the problem and upload it. If it online, you can take a screen shot with "print screen" on your keyboard in Windows and upload the screenshot.