Question

I just need some help on this problem I been stuck on.

Find the distance between parallel lines w/the equations 3x-5y=1 and 3x-5y=-3

Answer 1

The distance between a point (u,v) and a line a x + by + c = 0 is
\[
d=\frac{ |a u + b v +c | }{\sqrt{ a^2 + b^2}}
\]
Take a point (u,v) on the first line and apply this formula. You can take (u,v)=(2,1) for example

Answer 2

Write the lines as
3x-5y-1=0 and 3x-5y+3=0

Answer 3

\[
d=\frac{ |3(2) +(-5)(1) +3 | }{\sqrt{ 3^2 +5^2}}=
\frac{ 4 }{\sqrt{34}}=

\]

Answer 4

ohhh thank you I understand now

Answer 5

one more problem i been stuck on
find equations of the lines that bisect the acute and obtuse angles formed by the graphs of 6x + 8y = -5 and 2x - 3y = 4

Answer 6

Post is as a different problem and let me know about ti

Answer 7

will do