The expressions 22x^3+15x^2-4x-6 and 2+14x-12x^2-5x^3 have the same remainder when each is divided by x-a. Show that 27a^3+27a^2-18a-8=0. Use the substitution y=3a to find the values of a.

Question

anonymous · Answer

plug in x=a in both the polynomials and equate both .!

anonymous · Answer

u there ..?  or i should elaborate it all ?

anonymous · Answer

Okay,sorry i replied so late.

anonymous · Answer

But,it's x-a not x=a

anonymous · Answer

i know ..what i am telling is the application of remainder theoremremainder the

anonymous · Answer

Okay,I will try it.

anonymous · Answer

yeah ..try if u get stuck ...m there .!

anonymous · Answer

What's next?

anonymous · Answer

$$22a^3+15a^2-4a-6=2+14a-12a^2-5a^3$$

anonymous · Answer

above i have simply put "a" in place of x and equated them 
then just simply by transposing like terms...u will get ..!
...$$27a^327a^2-18a-8=0  $$

anonymous · Answer

Okay Thanks