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Chemistry 25 Online
OpenStudy (anonymous):

Two boxes of 15.0 kg are measure to be 0.85 m apart from center to center. What is the attractive gravitational force that exists between the two boxes?

OpenStudy (jfraser):

plug into the formula for universal gravitation. This is also physics, and better belongs in that group.\[F_G = \frac{G*M_1*M_2}{r^2}\]

OpenStudy (anonymous):

okay I am not sure which numbers to put into the parts of the equation. What does g and m represent?

OpenStudy (jfraser):

"G" is the universal gravitation constant, easy to look up. M1 and M2 are the masses of the objects

OpenStudy (anonymous):

okay! Awesome I think I can figure it out now.

OpenStudy (anonymous):

6.67*10^-11 is the universal gravitation.

OpenStudy (jfraser):

yes

OpenStudy (anonymous):

I keep getting 2.07 but I don't think that is right

OpenStudy (anonymous):

2.07*10^-8 N

OpenStudy (jfraser):

why not?

OpenStudy (anonymous):

Because I have 3 answers to choose from and that is not one of them. I thought that i got it right though.

OpenStudy (anonymous):

The closest one is 2.1*10^-8 N

OpenStudy (jfraser):

what's the real difference between 2.10 and 2.07?

OpenStudy (anonymous):

I guess it is not very much. So it will be 2.10.

OpenStudy (jfraser):

2.10*10-8N, don't forget the exponents

OpenStudy (anonymous):

Right. :) Thanks!

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