Algebra 9th grade help please! A medal will be rewarded! :)
@phi
@Phoenix515
Here's the question: Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 8^{x} and y = 2^{x + 2} intersect are the solutions of the equation 8^{x} = 2^{x + 2}. Part B Make tables to find the solution to 8^{x} = 2^{x + 2}. Take the integer values of x between -3 and 3. Part C: How can you solve the equation 8^{x} = 2^{x + 2} graphically.
@e.mccormick may I please have some help? I am having a hard time w/ this!
Anyone? antschauble I need some help.
are you solving it
Well, I am going to be leaving as soon as someone is ready.... but here is a graph to start with: https://www.desmos.com/calculator/i6iwc6vaud
Could you please explain? I don't understand.
Like I said, I don't have time. I am literally waiting for someone so we can walk out the door. Mathematically, here is a clue: \((a^m)^n=a^{m\cdot n}\) \(8=2^3\)
With the math info there, you can use \(\log_2\) to solve it.
ok, thank you!
@phi may i have some help?
@amistre64 may I have some help
i have time constrictions as well. srry
ok
@JM98SMITH may I have some help
@jhonyy9
which part did you do ?
None of them, I don't know what to do, could you please explain? I mean, I'm confused as to what to do. :/
Can you do Part B: Part B Make tables to find the solution to 8^{x} = 2^{x + 2}. Take the integer values of x between -3 and 3. for each x from -3 to +3, figure out 8^x and 2^(x+2) and put that into a table.
make 3 columns, with the headings "x", "8^x" and "2^(x+2)"
ok
I understand, so make a column for x, w/ the numbers going from -3,-2,-1,0 up to +3, plug those numbers into the equations above, and then what do I do for part c.?
Plot the points from part B, and connect the dots. you should get two curves that cross. where they cross is the answer.
Thank you so much for the help.
For Part A Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 8^{x} and y = 2^{x + 2} intersect are the solutions of the equation 8^{x} = 2^{x + 2}. Let's say that the point (x0,y0) "works" for both equations. In other words, we get \[ 8^{x_0}= y_0 \text{ and } 2^{x_0+2} = y_0 \] The point is both equations equal the same number y0. That means \[ 8^{x_0}=2^{x_0+2} \] and the number x0 is the solution. Because the point (x0,y0) is "on" both curves, it is the intersection of the two curves. The x value of the intersection point will be the answer
Join our real-time social learning platform and learn together with your friends!