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Mathematics 10 Online
OpenStudy (tester97):

Use the binomial theorem to expand the binomial. (s + 4v)^5 (1 point)

OpenStudy (tester97):

here are my answer choices s5 – 20s4v + 160s3v2 – 640s2v3 + 640sv4 – 1024v5 s5 + 20s4v + 160s3 + 640s2+ 1280s + 1024 s5 + 20s4v + 160s3v2 + 640s2v3 + 1280sv4 + 1024v5 s5 + 20s4v + 80s3v2 + 640s2v3 + 640sv4 + 1024v5

zepdrix (zepdrix):

\[\large\bf\sf =\text{_}s^5(4v)^0+\text{_}s^4(4v)^1+\text{_}s^3(4v)^2+\text{_}s^2(4v)^3+\text{_}s^1(4v)^4+\text{_}s^0(4v)^5\]

zepdrix (zepdrix):

I left spaces for the coefficients that we'll need.

zepdrix (zepdrix):

Understand how the basic expansion works though? The powers on s count DOWN from 5 as we move to the right. And the powers on 4v count UP to 5.

zepdrix (zepdrix):

The coefficients in front of each term ( where I left the _ ) is given by the 6th row of Pascal's triangle.

OpenStudy (tester97):

so the answer would be D?

zepdrix (zepdrix):

|dw:1389984275763:dw|

zepdrix (zepdrix):

Well it's certainly not A. We shouldn't have any subtraction showing up.

zepdrix (zepdrix):

\[\large\bf\sf =\color{#DD4747 }{1}s^5(4v)^0+\color{#DD4747 }{5}s^4(4v)^1+\color{#DD4747 }{10}s^3(4v)^2+\color{#DD4747 }{10}s^2(4v)^3+\color{#DD4747 }{5}s^1(4v)^4+\color{#DD4747 }{1}s^0(4v)^5\]

zepdrix (zepdrix):

Pascal's Triangle gives us those coefficients. You just need to simplify it down a little bit. Hmm I don't think it gives us D..

OpenStudy (tester97):

Im not really sure what the answer is i thought it was out of b or D and you said that D is incorrect so that mean that the answer is b?

zepdrix (zepdrix):

I don't understand, are you just guessing..? Did you try to do some of the multiplication? 0_o

OpenStudy (tester97):

IM sorry i just cant think today so please excuse me

OpenStudy (tester97):

It has been so stressful today can we just start from the beginning?

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