Question

Need help

Answer 1

draw and name all of the structural isomers that are ketones with five carbon atoms in its longest chain and the molecular formula C5H10O. Can this molecular formula also have an aldehyde structure? If so, illustrate and name the aldehyde. Can this be drawn as an ether? Explain.

Answer 2

Its goanna cost you a fortune..:p

Answer 3

Keytones have C=O bonds in the hydrocarbon chain. So you can arrange the C=O CH3 and CH2 in any way and get five different structural isomers, such as Ch3-Ch2-Ch2-CH2- HC=O to get an aldehyde. It includes the aldehydes, carboxylic acids, and even esters. However, you can't draw an ether if the oxygen is double bonded to a carbon. It must be something like R-O-R to be an ether. Ester is O=C-O-R. Where R is any group.

Answer 4

so u can have ketones, and aldehyde but no ether. Right?

Answer 5

The aldehyde are pentanal, 3 methylbutanl, 2-methylbutanal, and 2,2-dimethylpropanal?

Answer 6

is this right?

Answer 7

Naming of aldehydes: Choose the longest hydrocarbon chain, and add suffix --al. Your naming is correct. You didn't draw the hydrogens.

Answer 8

1) CH3-C-CH2-CH2-CH3 2-pentanone
||
O

2) CH3-CH2-C-CH2-CH3 3-pentanone
||
O

3) CH3-C-CH-CH3 Methyl isopropyl ketone (3methyl-2-butanol)
|| |
O CH3

ALDEHYDES:
1') CH3-CH2-CH2-CH2-HC=O Pentanal

2') CH3-CH2-O-CH=CH-CH3 -3-methylbutanol

3') OHC-CH(CH3)-CH2-CH3 -2-methylbutanol

how is this?

Answer 9

There's 1 degree of saturation, meaning there's either a double bond or a ring here. Total of 16 isomers.

Answer 10

20 isomers*

Answer 11

so how many in total do i have to list out?

Answer 12

If they didn't specify a number, I would draw all 20 isomers.

Answer 13

which is what I can't find anywhere on the internet about the isomers

Answer 14

tried to look it up and got nothing

Answer 15

Do you know \(what\) an isomer is??

Answer 16

a compound displaying isomerism with one or more other compounds.

Answer 17

Any of two or more substances that are composed of the same elements in the same proportions but differ in properties because of differences in the arrangement of atoms

Answer 18

Yes. And do you know what it means to have 1 degree saturation?

Answer 19

Chmvajay, r u going to help or just flippin watch?

Answer 20

not sure what 1 degree saturation is

Answer 21

It tells you whether you have double bonds or a ring basically. 1 degree saturation means you should look for a carbonyl or a carbon-carbon double bond, or a ring or an aromatic ring...
1 degree means you have either a double bond or carbonyl or a ring. But, only one.

Answer 22

Here is an example of what I mean:

Answer 23

And I don't know what that other person was talking about, but you can have an ether. I see \(\sf \color{Red}{two}\)

Answer 24

I'm confused of what to write for this question

Answer 25

For the question at hand, you have \(\sf \color{red}{9}\) isomers: 4 aldehydes, two ethers, and 3 ketones.

I'll leave it to you to draw them.

Answer 26

1) CH3-C-CH2-CH2-CH3 2-pentanone
||
O

2) CH3-CH2-C-CH2-CH3 3-pentanone
||
O

3) CH3-C-CH-CH3 Methyl isopropyl ketone (3methyl-2-butanol)
|| |
O CH3

ALDEHYDES:
1') CH3-CH2-CH2-CH2-HC=O Pentanal

2') CH3-CH2-O-CH=CH-CH3 -3-methylbutanol

3') OHC-CH(CH3)-CH2-CH3 -2-methylbutanol
are these some?

Answer 27

Can you draw them using bond line notation? It's easier and faster. You don't need to name them, just draw them.

Answer 28

so i have to get 9 isomers for this question?

Answer 29

For ketones are they methyl isopropyl, 2-pentanone, and 3-pentanone?

Answer 30

DRAW THEM!

Answer 31

pentanal, 3-methylbutanal, 2-methylbutanal,
ether:tetrahydropyran,2-methyltetrahydrofuran?

Answer 32

?

Answer 33

Yes, that's 2-methyl-3-butanone above, and 2 pentanone.

Answer 34

3-pentanone?

Answer 35

is it called 2-methyl-3-butanone or methyl isopropyl ketone?