Graph the relation {(5, 0), (0, 5), (5, 1), (1, 5)}. Is it a function? Why or why not?
if it's a function, that means that every input hads only one output. ususally, the first number in the ordered pair is the input and the second is the output.
y is not a function of x because two different x's give different y's ((5,0) and (5,1) if x is 5 then y can't both be 0 and 1. So I'd say no not a function.
these are my choices. A.Yes, it passes the horizontal-line test. B. No, it does not pass the horizontal-line test C. Yes, it passes the vertical-line test. D.No, it does not pass the vertical-line test..
@Drahgnus please read the code of conduct. don't just give out answers. instead help lead them to a place of understanding.
doesn't pass the vertical line test because at x = 1 there are two y's above it. Btw pgpilot archer vice is awesome
oh lol didn't know that sorry first 20 minutes on this site
yeah, i can't wait!
lol its ok. so my answer would be C.??
no worries, how did you get a score of 42 in 10 minutes?
nope answer is not C.
ohh...? does it pass the vertical??
so snap so it would be D. my bad
you tell me, what does it mean to pass the vertical line test?
I've answered like 20 questions they're all kinda simple here, I'm trying to get an answer to differential equation question. Look that type of math up and thats how :P Aerospace engineering ;) Imagine putting a vertical line at x = 1, does it hit more than one y when you do that?
funny, i have a degree in math and didn't get points that quick.
what kind of diffy q?
I wish I could both of you guys medals.. sorry I cant though
Give it to pg
did you get your question figured out, @PeytonPerez372 ?
no, i don't care. give it to Drahgnus
sorry guys you both were a big help though
that's why we're here
RAMPAAAAAGEEEEEE
LANA!!!!
SPLOOOSH
Bloody mary, blessed are you among wingspantails. Pray for me now in the hour of my death, which I hope is soon. Amen.
oh for my differential equation.. you have a degree in math? that might help... okay so its a homogenous differential, so youre supposed to use u = y/x y' = y/x + x / [(x^2 * y)^1/3 + (xy)^1/2 + x ]
i've literally waited my whole life to say these words... I'm comandeering this AIRBOAT!!!
hahahaha who do i remind you of?! burt reynolds in what?!
okay and what did you get after subbing?
GATOR
oh wait, the one before had the airboats... WHITE LIGHTNING!
I can't get it in a form of y/x that's my problem, I know in the end the y' = u + xu' and then the right side the first part is u + ... its just a mess I don't even know, I've tried dividing by xy^1/2 but it didn't look promising.. tried dividing by y.. just not working for me :\
okay, hold on a sec...
and I think the reason I received points so fast was because I just gave them the answer, didn't show any work and did that to like 30 simple problems lol.
thanks a lot :D if you want I can link you to my question after so you can get a medal
so did you get \[y'=\frac{u'x^2+y}{x}\]
you guys are like trolling my question lol
sorry this should be a link to my question http://openstudy.com/users/drahgnus#/updates/52d979fae4b05ee05437f785
sorry @PeytonPerez372
Join our real-time social learning platform and learn together with your friends!