Find the circumcenter of the triangle ABC. A(1,3), B(4,3) C(4,2). I keep getting stuck. Help me with the steps
PLEASE
\(\bf \textit{Centroid of a Triangle} \begin{array}{llll} A(x_1,y_1)\quad B(x_2,y_2)\quad C(x_3,y_3)\\ \quad \\ \left(\cfrac{x_1+x_2+x_3}{3}\quad ,\cfrac{y_1+y_2+y_3}{3}\quad \right) \end{array} \)
circumcenter = centroid
The circumcenter is the point of intersection of the three perpendicular bisectors. Find the slopes of any two sides, say AB and BC. The slope of the perpendicular line will be the negative reciprocal of the slope of the line. Find the midpoints of AB and BC. Midpoint of a line segment is: ( (x1+x2)/2, (y1+y2)/2 ). Knowing the slope and knowing the midpoint through which the line passes you can find the equation of the perpendicular bisectors. The point where the perpendicular bisectors intersect will be the circumcenter.
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