Find an equation for the line with slope m through the point (a,c). ***I'm just forgetting some of the small steps... Could someone please refresh me? I know you start off with y=mx+b... I just forgot how to create the equation when you're using variables! THank you!!!:)
\(\bf \begin{array}{lllll} &x_1&y_1\\ &({\color{red}{ a}}\quad ,&{\color{blue}{ c}})\quad \end{array} \\\quad \\ slope = {\color{green}{ m}} \\ \quad \\ y-y_1={\color{green} m}(x-x_1)\) plug and chug, and solve for "y"
ohhh so you're using point slope form for this one?
Well lets start from the easiest part - slope - this is the multiplier of the x As such your equation becomes y = mx + T where t we need to find out. since the line passes through point (a,c) then you know that when x = a, y =c as such c = ma + t - all thats left is solve for T
so y-c=m(x-a) ?
yes, to get the equation, yes, you'd use the point-slope form
yeap
so do i distribute now?
and you can solve that for "y" to set to slope-intercept form
okay, so now it's y-c=mx-ma ?
@Garm when you say t, do you mean the y-int? :/
T is just unknown like x
solving for t and then substituting it into previous equation will yield an answer
ohhh i see :) and @jdoe0001 how do we solve for the "y" ?
add "c" to both sides
turn formula into something that looks like y=.....
okay, just want to make sure i'm following correctly so far :) are these the correct steps so far? y-y1=m(x-x1) y-c=m(x-a) y-c=mx-ma +c +c = y=mx-ma+c ??
did I do that last part right? :/
yes
okay awesome!! :) do i do something after that? or is that the final equation? :/
well you know m a and c as such you have nothing else unknown in your equation but x and y - therefore it is a valid formula to draw a line =)
essentially that is what you are looking for - you need to make sure you only have 2 unknowns for function
how do i do that? so from y=mx+ma+c, what do I do?
well what else you dont know in that formula but x and y?
we don't know m ? a and c?
you do
did I do that last part right? \(\large \checkmark\)
m a and c were given to you in the question
as such they are not unknowns they are essentially just abstract numbers
ohhh haha okay but y=mx-ma+c has to be simplified more? am I understanding that right? or is that the final equation?
@jdoe0001 yes all your stuff is top notch
^^agreed :P and i love the latex! i can never remember how to do the latex stuff haha
@iheartfood nope! =) that's the beauty of algebra - you dont need to know the answer as number to actually have correct answer.
awesome!! so the problem is done?! :O it's just y=mx-ma+c ?
indeed - because you cannot simplify it further.
okay great!!! :) thank you so much!! @jdoe0001 @Garm I had totally forgotten how to do this with variables and this cleared it up! Thanks again :)
yw
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