Question

simplify expression
e^-2-f^-1/ef

Answer 1

Try entering that in the equation editor, it's a bit unclear.

Answer 2

Can you rewrite it using LaTex? That's a bit difficult to read. It can be taken various ways.

Answer 3

yes

Answer 4

\[\frac{ e ^{-2}-f ^{-1} }{ ef }\]

Answer 5

\(\sf e^{-2}=\frac{1}{e^2}\), and similarly, \(\sf f^{-1}=\frac{1}{f}\)

Answer 6

@Sephora f-e^2/f^2e^3

Answer 7

tequila i dont understand

Answer 8

@Sephora That's the answer

Answer 9

how did you got that answer please show me. I want to learn

Answer 10

Don't just give answers @tequila4 that's not very helpful for the user and as you can see, they are trying to learn.

Answer 11

Thank you abbot

Answer 12

It might help if you separated them into two fractions: \(\sf \color{red}{\frac{e^{-2}}{ef}-\frac{f^{-1}}{ef}}\)

Answer 13

okay

Answer 14

Remember, when you have a negative exponent like you do here: \(\sf \color{blue}{e^{-2} ~it~simply~means:\frac{1}{e^2}}\)

Answer 15

So, you actually have: \(\sf \color{red}{\frac{1}{e^2(ef)}-\frac{1}{f(ef)}}\)

Answer 16

Do you follow me so far, @Sephora ?

Answer 17

yes

Answer 18

You then multiply across. Remember that when you multiply across parenthesis, you are actually ADDING their exponents, so it's \(\sf \color{red}{e(ef) = e^{1+1}f = e^2f}\), now you try the second one.