Question

An inlet tap A inlets water at 2 litre/min and another tap B inlets water at 3 litre/min. There is an outlet pipe at the bottom, which can empty the tank in 10 hours. If all the three taps were kept on, the tank had been filled in 8 hours. What is the capacity of the tank?

Answer 1

volume=rate*time. let r be the rate of pipe C
v=r*10 (There is an outlet pipe at the bottom, which can empty the tank in 10 hours)
v=(2+3-r)*8 (If all the three taps were kept on, the tank had been filled in 8 hours)
solve for v

Answer 2

no we have another variable r

Answer 3

10r=40-8r==>r=20/9

Answer 4

1/2+1/3+1/x=1/8,
x=17/24,

Answer 5

Rate for A is 2 liters/min
Rate for B is 3 liters/min
Total inflow is 5 liters/min =300 liters/hr

Outflow is v/10 liters/hr where v is volume of tank

(Inflow-outflow)*8 = v

Answer 6

24000=18v,v=1333.33liters

Answer 7

Yep. Check answer: outflow is 133.3 l/hr so net inflow is 300-133.3=166.7 l/hr
166.7*8=1333.6

Answer 8

If we left answer in fractional form check would be exactly correct.