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Calculus 2 - Antiderivatives
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\(\large F'(x) = f(x)\) integrate both sides \(\large F(x) = \int f(x) dx = \int \frac{1}{4}x dx\)
take the integral ?
x^2/8?
@ganeshie8
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\(\large F(x) = \int \frac{1}{4}x dx = \frac{x^2}{8} + c\)
since we're given \(F(0) = 0\), plugin x = 0 in F(x) :- \(0= 0 + c \implies c = 0 \) so, the required function will be \(\large F(x) = \frac{x^2}{8}\)
when u take indefinite integral, u wil always get the constant \(c\), dont forget it ok
ok, right
wat do u think about second part ?
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somehow get c
??
Is there oly one possible solution ? the answer is yes. cuz, we oly got one solution when \(c = 0\)
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