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OpenStudy (anonymous):

A photon of wavelength 350nm and intensity 1.00W/m2 is directed at a Potassium surface (Work Function = 2.2 eV). Will photoelectrons be emitted from the surface?

OpenStudy (anonymous):

Need to find energy of photon from wavelength. E = h f c = f lambda f= frequency, lambda = wavelength, c is speed of light. Once you have energy, see if it exceeds work function, so that electron is emitted.

OpenStudy (anonymous):

6.63 × 10^-34 × (3 × 10^8 ÷ (350 × 10^-9)) - (2.2 × (1.6 × 10^-19)) = 2.1628571e-19 So there will be photoelectric effect?

OpenStudy (lastdaywork):

@Thame If hf >= work function; then (and only then) electrons will be emitted

OpenStudy (anonymous):

Ok thanks.

OpenStudy (lastdaywork):

Although, be careful with the units (like here work function is in eV)

OpenStudy (anonymous):

Yes so Ive converted the ev to joules by multiplying 2.2 by 1.6x10^-19

OpenStudy (lastdaywork):

It was hard to understand your calculations, so I advised you anyway :)

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