A photon of wavelength 350nm and intensity 1.00W/m2 is directed at a Potassium surface (Work Function = 2.2 eV). Will photoelectrons be emitted from the surface?
Need to find energy of photon from wavelength. E = h f c = f lambda f= frequency, lambda = wavelength, c is speed of light. Once you have energy, see if it exceeds work function, so that electron is emitted.
6.63 × 10^-34 × (3 × 10^8 ÷ (350 × 10^-9)) - (2.2 × (1.6 × 10^-19)) = 2.1628571e-19 So there will be photoelectric effect?
@Thame If hf >= work function; then (and only then) electrons will be emitted
Ok thanks.
Although, be careful with the units (like here work function is in eV)
Yes so Ive converted the ev to joules by multiplying 2.2 by 1.6x10^-19
It was hard to understand your calculations, so I advised you anyway :)
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