Question

Write the equation of a line that is parallel to the line 2x - 3y = 5 and passes through the point (2,-1).

Answer 1

Gradient will be the same, so put the constant as c, plug in the new coordinates and you'll get c, reform the equation, give it a shot :) (Use y = mx + c and make y the subject of the equation)

Answer 2

is it 3x+2y=5, 3x-2y=7,2x-3y=7, or 2x+3y=1?

Answer 3

you first need to find the slope of the equation given. Do you know how to do that ?

Answer 4

i got 3y -2x = -7, as y = 2/3x - 5/3, take 5/3 = c, you get
y = 2/3 x + c, and then replace x and y with 2, -1. Solve it you get c = -7/3
now plug it all in. :P

Answer 5

2x - 3y = 5
-3y = -2x + 5
y = 2/3x - 5/3
slope is 2/3.
A parallel line will have the same slope.

now we will use y = mx + b
slope(m) = 2/3
(2,-1) x = 2 and y = -1
now sub into y = mx + b and solve for b
-1 = 2/3(2) + b
-1 = 4/3 + b
-1 - 4/3 = b
-3/3 - 4/3 = b
-7/3 = b
so your parallel equation is : y = 2/3x - 7/3 but you need it in standard form.
Ax + By = C
y = 2/3x - 7/3 --multiply by 3
3y = 2x - 7 -- subtract 2x
-2x + 3y = -7 -- multiply ny -1 to make x positive
2x - 3y = 7

mathbreaker is correct :)