Question

Question in attachment

Answer 1

@surjithayer

Answer 2

@primeralph

Answer 3

@bagajr

Answer 4

@surjithayer how did you get it?

Answer 5

correction
y=-0.5sin2x

Answer 6

when x=0,y=0,\[when x= \frac{ \pi }{2 },y=0,when~x=\frac{\pi }{4 },y=-0.5,\sin 2x=\sin2*\frac{ \pi }{4 }=\sin \frac{ \pi }{2 } =1\]
-0.5*1=-0.5
hence y=-0.5 sin 2x

Answer 7

and part b?@surjithayer

Answer 8

when x=0,y=2
\[when x=\frac{ \pi }{ 2 },\frac{ 3\pi }{2 },-\frac{ \pi }{2 },.....\]
y=0
y=2cos x
(\[\cos 0=1,\cos \pi=-1,\cos 2\pi=1.....\])