Question

If f(x) = x 2 + 1 and g(x) = 3x + 1, find [f(4)] 2.

Answer 1

lol kinda like that yeah

Answer 2

If f(x) = x 2 + 1 and g(x) = 3x + 1, find [f(4)] 2. the twos are squares

Answer 3

is it like this ? \[[f(4)]^{2} \]

Answer 4

yes it is

Answer 5

\[f(x) = x ^{2} + 1 \] and \[g(x) = 3x + 1\]

Answer 6

yes

Answer 7

then the last two on end of find f..... is a square too

Answer 8

Ok,

See when you have exponents like, \[(x ^{a})^{b}\] than you just multiply them,

\[^{a}*^{b} = ^{ab}\]

\[(x)^{ab}\]

So in, x^2 plug in 4 for x

\[f(4) = (4^{2})^{2} \rightarrow 4^{4} \rightarrow 256 \]

f(4) = 256 + 1
257

f(4) = 257

Answer 9

wow so helpful :)

Answer 10

For g(x) do the same,

\[g(4) = 3(4)^{2} + 1 = 12^{2} + 1 \rightarrow 144 + 1 = 145\]

g(4) - 145

Answer 11

g(4) = 145 *