Help with evaluating a fraction!
\[-\frac{ 1 }{ 8\cos ^{3}(t) }|t=\frac{ \pi }{ 4 }\]
please show work as obviously I can enter it into a calculator if I just want the answer.
go to www.wolframalpha.com, besides answer, it will show u steps and graphs
that is what i use all the time
not helpful. but thanks
\[\frac{ -1 }{ 8(\frac{ \sqrt{2} }{ 2 })^3}=\frac{ -1 }{ 8(\frac{ 2\sqrt{2} }{ 8 }) }=...?\]
this is how I am trying to solve this. \[=-\frac{ \sqrt{2} }{ 4 }\] is the correct answer.. but I cannot figure out for the life of me how to get there.
\[\Large\bf\sf -\frac{1}{8\left(\cos t\right)^3}\quad=\quad -\frac{1}{8\left(\cos \frac{\pi}{4}\right)^3}\quad=\quad -\frac{1}{8\left(\frac{\sqrt2}{2}\right)^3}\]
So I see you posted some steps, where are you getting stuck?
\[\Large\bf\sf -\frac{1}{2\sqrt2}\]Rationalize ( get the irrational sqrt2 out of the denominator ) by multiplying top and bottom by sqrt2,\[\Large\bf\sf -\frac{1}{2\sqrt2}\left(\frac{\sqrt2}{\sqrt2}\right)\quad=\quad -\frac{\sqrt2}{2\cdot2}\]
Was it just the last step that you didn't understand?
yes!
sorry was dealing with other things. Thank you Zep!
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