please help with functions
It's a function..
The graph is a function because it obeys the vertical line test.
In every one value of x, there is exactly one value of y.
@liliegirl I think you are talking of the horizontal line test.
In mathematics, a function is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly ONE output.
Hey, trollface, I agree with you that the "vertical line test' applies here, and that for each x value you'll associate exactly one y value. So: does the given graph represent a function or not/
cOOL.
Could you, trolley, explain what the horiz. line test is for?
@Isaiah.Feynman Horizontal line test is used to determine if the function is injective. right?
You may not have been exposed to this "test" before. Sometimes we have to decide whether a given function as an inverse. If a horiz. line drawn thru the graph of the given fn. hits it in only one place, then the function does have an inverse. If two or more places, the given fn. doesn't have an inverse. Just for ref.
@trollface that definition is for the horizontal line test. Not the vertical line test. The vertical line test, tests to see if the graph of some equation is a function. If the vertical line intersects the graph once then the equation is a function. If it intersects the graph more than once then the equation is not a function. The horizontal line test, tests to know if a function is one to one. A one to one function has only one y value for every x value. Graphically if a horizontal line intersects the graph of a function once then the function is one to one. If it intersects the graph more than once then the function is not one to one.
Thanks for pointing this out, Isaiah. I'd substitute "inversible" for "injective." But I think we're on the same wavelength. :)
Thank you @mathmale i'll definitely note that down for future reference.
IF. I believe trollface already knew that, judging by his responses earlier. But thanks for the very nice summary, which is quite accurate.
Aah, I understand now, I was getting it a little mixed up, thanks for the thorough explanation. @Isaiah.Feynman
for he's a jolly good fellow, which nobody can deny!
:) over and out.
agreed :) @mathmale thanks again!
Bye!
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