Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

Andrea is designing the seating arrangement for a concert in her local park. To give everyone a good view, each row must have four more seats than the row before it, and the first row can only have 10 seats. Help Andrea plan the rest of the seating by solving for how many seats are in row 20. Then explain to Andrea how to create an equation to predict the number of seats in any row. Show your work, and use complete sentences. @ganeshie8

OpenStudy (anonymous):

too long to read

ganeshie8 (ganeshie8):

yes lol, however oly useful info we need to work is :- each row must have four more seats than the row before it, and the first row can only have 10 seats.

ganeshie8 (ganeshie8):

first row : 10 second row : ?

OpenStudy (anonymous):

hi @woohoo long time no see

OpenStudy (anonymous):

@Opcode

OpenStudy (anonymous):

yeah @ryanvarghese12790 been busy lately

OpenStudy (anonymous):

@ryanvarghese12790 can you help pls?

OpenStudy (anonymous):

1 sec

OpenStudy (anonymous):

any more q?

OpenStudy (anonymous):

@ryanvarghese12790 can you explpain cuz i didnt understand that explantion

OpenStudy (anonymous):

@Potatoes.ramu

OpenStudy (potatoes.ramu):

I think there are 90 seats in the 20th row.. Because here n=10(Because the first row has 10 seats) And each row behind that has to have four more seats. So that's four seats more than the preceding row...

OpenStudy (potatoes.ramu):

Oh oops wait. The number of seats in the 20th row is 86!

OpenStudy (anonymous):

I thnk it is 204 cuz, 10*20+4 = 204

OpenStudy (anonymous):

whats the formula for this arthimetic equation

OpenStudy (potatoes.ramu):

Let s be the number of seats in the first row. So s=10. Then there are s+4(n-1) seats in the n-th row. n is any positive integer.

OpenStudy (potatoes.ramu):

The equation in s+4(n-1)

OpenStudy (potatoes.ramu):

It's in series, so that's the equation :) @woohoo

OpenStudy (potatoes.ramu):

@ryanvarghese12790 , you can't use that formula, because the number of seats keep increasing in each row.

OpenStudy (anonymous):

so, 10+4(20-1) 14(19) = 266?

OpenStudy (potatoes.ramu):

No what is that? Substitute n=20 in the equation I gave you to find the number of seats in the 20th row! :)

OpenStudy (anonymous):

you all crazy i have no idea what the answer is !!!!!:D

OpenStudy (anonymous):

so, 10+4(20-1)

OpenStudy (potatoes.ramu):

The answer is 86! And the equation is s+4(n-1)! :P

OpenStudy (potatoes.ramu):

@ryanvarghese12790 exactly! :P

OpenStudy (anonymous):

that is wht I have done above

OpenStudy (potatoes.ramu):

And you get 86! So that's the number of seats in the 20th row!

OpenStudy (anonymous):

ok is there a name for this formula? @Potatoes.ramu

OpenStudy (anonymous):

nope not at all

OpenStudy (potatoes.ramu):

It's an arithmetic progression

OpenStudy (anonymous):

how wan 14* 19 = 86

OpenStudy (potatoes.ramu):

For instance in this series the common difference d=4

OpenStudy (potatoes.ramu):

@ryanvarghese12790 why are you multiplying 14 and 19. Multiply 4 and 19 and then add 10 to that.

OpenStudy (anonymous):

ok

OpenStudy (potatoes.ramu):

So the series goes like this. s, s+d, s+2d...... s+(n-1)d. s+(n-1)d is the nth term.

OpenStudy (potatoes.ramu):

s is 10 in this case. Because the first row has 10 seats. So we start with ten, And the series starts with ten.

OpenStudy (potatoes.ramu):

@woohoo

OpenStudy (anonymous):

wouldnt this equation work a_n=a_1+d(n-1) @Potatoes.ramu

OpenStudy (potatoes.ramu):

Nope.. that doesn't work! Use this one! It's definitely the right answer! Plus you get a negative sign if you subtract a and n

OpenStudy (anonymous):

the formula is called Arithmetic formula for sequences and it is a_n=a_1(n-1)d

OpenStudy (anonymous):

i know im ALOT late but i understand what @potatoes.ramu is saying. |dw:1435627221031:dw| thanks for the help i really needed this.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!