Question

Solve the exponential equation
2^x=4^x+1

Answer 1

Or 2(x)=4(x+1) I

Answer 2

2^x=4^(x+1)
2^X=2^2(X+1)
x=2(x+1)
x=2x+2
x=-2

Answer 3

I don't know how did @mohammad.arqum get the second step?

Answer 4

I USED...................
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THE POWER OF MATH...

Answer 5

but it is \[4^{(x+1)}=2^2(x+1)\]\[4^{(x+1)}=4 \times (x+1)\]

true or false?

Answer 6

This is supposed to be\[2(x)=4(x+1)\]\[2x=4x+4\]\[2x\color{blue} {-4x } =4x+4\color{blue} {-4x } \]\[-2x=4\] \[......\]

Answer 7

i cant understand what u are writing its all scrambled and stuff \[2(x)=4(x+1)\]\[2x=4x+4\]\[2x\color{blue} {-4x } =4x+4\color{blue} {-4x } \]\[-2x=4\] \[......\]

Answer 8

The question is without any exponents, the simplest algebra.

expand the parenthesis on both sides, subtract 4x from both sides, and then the final step that the user should know how to do.

what you wrote was amorphous...

Answer 9

Go over your work, you should be able to see your mistake, if not, then I would suggest use this site as an asker, or someone that needs help, rather then helper.

Answer 10

NNOOOO......the answer i wrote was correct u're mixing up the question the question was

Answer 11

you didn't write the question correctly, sir, I don't see that the person who asked the question, mentioned any exponent in his problem? you are doing something very complicated, instead of taking the BASIC APPROACH. Your answer is correct though, apologize for this, but why are you doing that way?

Answer 12

He wrote it 1st with exponents, but the re-wrote it.

Answer 13

2^x=4^(x+1)
this was the question as the questioner has told there are exponents
the rewrite was supposed to define the question more to remove any misunderstandings telling that (x+1) was a power not that x was only a power with 1 added later

Answer 14

If you understand "2(x)=4(x+1)" as a problem with exponents, then discussing anything any farther, is a waste of time.

Answer 15

FACEPALM leave it wud ya

Answer 16

okay nvm, I am not wasting my time on this any more.