Question

Using the function y=x^3−2x^2−3x+4, approximate the slope to the curve at x = 2

Answer 1

@Loser66

Answer 2

help please

Answer 3

take derivative, what do you have?

Answer 4

Why are they asking for an approximation? Have you not been taught derivatives yet?

Answer 5

@Loser66 can you show me what you mean??

Answer 6

to find the slope of the curve, we have to take derivative of the curve and then plug the point in to get the slope of the curve at that point
If you don't study derivative yet, you need @ranga help, hehehe because I forgot how to find the slope by approximation way

Answer 7

But cupcakezz would not answer my question if derivative has been taught yet and so I am not able to help.

Answer 8

@ranga we were, but I don't fully understand it

Answer 9

can you show me how to get the answer
??

Answer 10

to approximate, pick another point near x=2 (e.g x = 2.001) and use slope formula to find the slope.

Answer 11

If you have been taught derivatives then you can find the EXACT slope at x = 2. But here they are asking you to approximate the slope at x = 2. Follow sourwing's suggestion above.

Approximate slope at x = 2 is: { f(2.001) - f(2) } / 0.001 = ?

Answer 12

f(x) = x^3−2x^2−3x+4
f(2.001) = (2.001)^3 - 2((2.001)^2 - 3(2.001) + 4 = ?
f(2) = 2^3 - 2(2)^2 - 3(2) + 4 = ?

Then plug it into the formula:
Approximate slope at x = 2 is: { f(2.001) - f(2) } / 0.001 = ?

Answer 13

thanks @ranga