A certain substance has a heat of vaporization of 65.25 kJ/mol. At what Kelvin temperature will the vapor pressure be 6.00 times higher than it was at 319 K?

please help

Question

A certain substance has a heat of vaporization of 65.25 kJ/mol. At what Kelvin temperature will the vapor pressure be 6.00 times higher than it was at 319 K?

please help

wolfe8 · Answer

So P/T is constant so you have:
$$\frac{ P _{1} }{ T _{1} }=\frac{ P _{2} }{ T _{2} }$$ and you have P1, T1, and P2=6P1 and you are looking for T2

anonymous · Answer

ummm could you write that better...it doesn't show in equation form for me

wolfe8 · Answer

Oh maybe it's not working for you. So I wrote P1/T1=P2/T2

anonymous · Answer

oh ok so it will be T2=6p1/(T1P2)

anonymous · Answer

also, i dont have the pressure

wolfe8 · Answer

Substitute P2 with 6P1. You will end up cancelling the P :)

petiteme · Answer

Go Wolfe! :))

anonymous · Answer

so it will be t2=1/6t1

wolfe8 · Answer

Hmm something looks weird. Here's what I did:
P1/T1=P2/T2
(P1/T1)T2=P2
T2=P2(T1/P1)
T2=6P1(T1/P1)
T2=6T1

anonymous · Answer

i got it

wolfe8 · Answer

Alright good job.