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Mathematics 24 Online
OpenStudy (anonymous):

Two main isotopes of nitrogen, N-14, atomic mass=14.003amu, with relative abundance=99.63%; and N-15, atomic mass=15.00 amu with relative abundance=0.37%. what is the atomic mass of nitrogen?

OpenStudy (anonymous):

How about (0.9963)(14) + (0.0037)(15) ?

OpenStudy (anonymous):

\[\frac{ 14.003*99.63+15*0.37 }{ 100 }\] solve it.

OpenStudy (anonymous):

douglaswinslowcooper i get 14.0037 and surjithayer i get 1395.17439

OpenStudy (anonymous):

which one is the answer

OpenStudy (anonymous):

I was wrong, used 14 instead of 14.003, which is needed, . Correct answer (0.9963)(14.003) + (0.0037)(15.00)= 14.007. You can see it must average a bit more than 14 because both isotopes are heavier than 14.

OpenStudy (anonymous):

Thanks for medal. Glad to have helped.

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