Question

Find four consecutive integers, such that the product of the first and second integers minus 2 is equal to 3 times the product of the third and fourth integers.

Answer 1

@Mertsj

Answer 2

help please

Answer 3

Do you know how to represent 4 consecutive integers?

Answer 4

-6 -5 -4 -2?

Answer 5

-3**

Answer 6

No.
x
x+1
x+2
x+3

Answer 7

Now using that, you can write the equation.

Answer 8

(x+1)(x+2)(x+3)

Answer 9

x(x+1)(x+2)(x+3)

Answer 10

What is the product of the first and second ones?

Answer 11

-1, -2 ?

Answer 12

@Mertsj

Answer 13

x=first of four consecutive integers
x+1= second of four consecutive integers
x+2= third of four consecutive integers
x+3 = fourth of four consecutive integers

Answer 14

What is the product of the first and second of the four consecutive integers?

Answer 15

I dont get it :( @Mertsj

Answer 16

can you show it to me please :( ?

Answer 17

@Loser66

Answer 18

@partygirl do you know how to solve this?

Answer 19

-2, -1,0,1 or -5,-4,-3,-2

Answer 20

how would I explain though @Arddhendu

Answer 21

Let the consecutive integers be x, x+1, x+2, x+3
As per the question
x(x+1)-2=3(x+2)(x+3)
x^2+x-2= 3x^2+15x+18
2x^2+14x+20=0
2(x^2+7x+10)=0
x^2+7x+10=0
x^2+2x+5x+10=0
x(x+2) +5(x+2)=0
(x+2)(x+5)=0
so, x+2=0 or x+5=0
so, x= -2 or -5
If x =-2, then the 4 consecutive integers are -2, -2+1, -2+2, -2+3 i.e., -2, -1, 0,1
If x=-5, then the 4 consecutive integers are -5, -5+1, -5+2, -5+3 i.e., -5, -4, -3,-2

Answer 22

is that everything ? @Arddhendu

Answer 23

yes

Answer 24

ok Im going to write it exactly how you wrote it

Answer 25

thank you so much ! @Arddhendu