Question

exponent properties

Answer 1

y^10 / y^13

Answer 2

I have to simplify it

Answer 3

when you divide exponents you subtract them...

Answer 4

alright! thanks! and what about when it's z^-2

Answer 5

what do you mean? is there a second term

Answer 6

no it's just z^-2

Answer 7

is it already simplified?

Answer 8

not sure on that one.

Answer 9

okay and few more if thats okay with you

Answer 10

1/c^-7

Answer 11

would it be c^-7

Answer 12

im not sure what the answer is , but its definitely not c^-7 lol

Answer 13

okay and what about

Answer 14

x^3 y^5 / x^6 y^2

Answer 15

if i had to answer id say c^7 because the one makes it an inverse

Answer 16

are the x^3 and y^5 over eachother/

Answer 17

no thyre next to each other

Answer 18

hm i m going to leave this to bloopman. cx

Answer 19

i don't want to give wrong answers sorry

Answer 20

thats okay thanks

Answer 21

It is asking you to put in another form.
For (y^10)/(y^13) (and God knows why in the hell someone would be working with odd exponents like this), you simply use the rule of division to obtain that this expression is equal to y^(10 - 13) = y^(-3) = 1/(y^3).

Answer 22

Now, for 1/(c^(-7)), we know that this is equal to 1/(1/(c^7)), which is just c^7. However, another (more interesting, in my opinion) way of proving this is that 1 = c^0.
(c^0)/(c^(-7))
Now we just subtract exponents to obtain c^7.

Answer 23

so is it y^-3 ?

Answer 24

Yes.

Answer 25

yay i was right c:

Answer 26

okay and what about

x^3y^5 over x^6y^2

Answer 27

@bloopman

Answer 28

(x^3 * y^5)/(x^6 * y^2)
This can also be written as:
(x^3)/(x^6) * (y^5)/(y^2)
So what do you think the answer is?

Answer 29

x^9 y^7 or x^18 y^10

Answer 30

@bloopman

Answer 31

Neither. We're dividing, not multiplying

Answer 32

x^-3 y^-3 @bloopman

Answer 33

The first part is correct, but you messed up on the exponent of the latter term.

Answer 34

Anything with a negative exponent turns into a fraction with 1 on the top and the exponent with the base on the bottom of the fraction.

Answer 35

ohh it's just 3

Answer 36

x^-3 * y^-3 is 1/(x^3y^3)

Answer 37

what about this:

xy^-2/z^-4

Answer 38

That turns to xz^4/y^2

Answer 39

why

Answer 40

to make them positive?

Answer 41

The x stays on top because it is not part of y^-2. y^-2 goes to the bottom because y^-2 is (1/y^2). z^-4 is on the bottom, so it moves to the top since you can't have negative exponents.

Answer 42

(1/(1/z^4) = z^4. (z^-4) is the 1/z^4

Answer 43

okay!

Answer 44

Basically, you have a complex fraction due to the negative exponent which you need to simply. (Which is why you move them up/down)

Answer 45

Anything else?

Answer 46

what is there is just z^-2

Answer 47

Then it would be xz^2/y^2.

Answer 48

no I meant like just z^-2

Answer 49

how would i simplify that

Answer 50

z^-2 is

1/ z^2

Answer 51

You move it to the bottom, and the 1 is in the numerator. z^2 = (z^2)/1. Anything over 1 is itself.

Answer 52

last one: q^0

Answer 53

Anything to the power of 0 is 1.

Answer 54

so 1q or just 1

Answer 55

Just 1

Answer 56

okay I have a harder one to do but I dont wanna bother u

Answer 57

I'm open

Answer 58

okay my computer wont let me draw or insert equations today so I will write it out again

Answer 59

unless I can take a picture of it hold on

Answer 60

@larryboxaplenty

Answer 61

You want to take on one fraction at a time than multiply them together.

Answer 62

where would i start

Answer 63

sorry, I have to go, but do you know how to distribute exponents?

Answer 64

no..