sine of x divided by one minus cosine of x + sine of x divided by one minus cosine of x = 2 csc x

Question

agent0smith · Answer

Nope. Not doing that with no equation editor.

anonymous · Answer

what do you mean

agent0smith · Answer

Too hard to type w/o a working equation editor.

anonymous · Answer

how about just like (sinx/(1-cosx)) + (sinx/1-cosx)) = 2 cscx

agent0smith · Answer

Add the fractions of the LHS, they have the same denominator.

Then multiply the top and bottom of the LHS by (1+cos x), and then do stuff.

agent0smith · Answer

Btw this is NOT an identity. Both sides are not equal.

anonymous · Answer

thank you!

kobeni-chan · Answer

If this is from the class I think it is, the question actually was (sinx/(1-cosx)) + (sinx/1->+<-cosx)) = 2 cscx. Part of the text of the problem is an image, and when you copy & paste, it gives you the wrong thing...

kobeni-chan · Answer

@Astrophysics do you think you could help me with this?