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OpenStudy (anonymous):
s=1/2gt^2+vt for v
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OpenStudy (anonymous):
you are just trying to solve this for v?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
subtract 1/2gt^2 from both sides, then divide both sides by t. does this make sense?
OpenStudy (anonymous):
yeah but then when i divided i got stuck on what happens with the 2 and the v in the bottom of the fraction
OpenStudy (anonymous):
ok one sec.
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OpenStudy (anonymous):
i meant 2 and t sorry
OpenStudy (anonymous):
\[\frac{ s-\frac{ 1 }{ 2 } g*t^2 }{ t }=v\]
OpenStudy (anonymous):
when you divide fractions, you know that you multiply by the reciprocal.
OpenStudy (anonymous):
so s-1/2gt^2 + 1/t just cancels out one of the t's from the numerator. You can write the gt in the numerator so \[v=s-\frac{ g*t }{ 2 }\]
OpenStudy (anonymous):
\[\frac{ 1 }{ 2 }g*t^2*\frac{ 1 }{ t }\]
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OpenStudy (anonymous):
i completely forgot about multiplying by the reciprocal. thats why i was so stuck on that t
OpenStudy (anonymous):
awesome. so it worked out?
OpenStudy (anonymous):
i haven't tried it yet
OpenStudy (anonymous):
its sometimes eaiser to see if you write the gt^2 in the numerator i guess... sorry
OpenStudy (anonymous):
\[v=s-\frac{ g*t^2 }{ 2 }*\frac{ 1 }{ t }\]
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OpenStudy (anonymous):
yes it works :)
OpenStudy (anonymous):
thanks :)
OpenStudy (anonymous):
awesome. good luck.
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