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Chemistry 19 Online
OpenStudy (anonymous):

Ammonia, NH3, is produced through a combination reaction involving N2(g) and H2(g). If 24.0 mol of H2(g) react with excess N2(g), how many moles of ammonia are produced?

OpenStudy (anonymous):

I need to know how to solve this, I'm a bit rusty on my moles.

OpenStudy (wolfe8):

First, make sure the equation is balanced. Next, can you find the number of moles of whatever substance you have? Use this: http://www.ptable.com/

OpenStudy (wolfe8):

I mean, write a balanced equation first.

OpenStudy (anonymous):

So..\[N _{2}(g) + h _{2}(g) \rightarrow NH _{3}\]

OpenStudy (anonymous):

Is that the right equation?

OpenStudy (anonymous):

\[N _{2}+3H _{2} \rightarrow 2NH _{3}\]

OpenStudy (wolfe8):

Oh my the equation editor is not working for me but I can see it. From here can you just use normal typing? Notice that the equation is not balanced. You have 2 N on the left and one on the right. And you have 2 H on the left and 3 on the right.

OpenStudy (anonymous):

so N2 + 3H2 = 2NH3

OpenStudy (wolfe8):

Right. So now, you know how much H2 you used. Can you fine the number of moles of it? http://erhs.rcsnc.org/UserFiles/Servers/Server_4766394/Image/Donna%20Scofield/mole%20conversion%20map.bmp

OpenStudy (anonymous):

Uh...Walk me through?

OpenStudy (wolfe8):

Sure. Do you know how to find the number of moles?

OpenStudy (anonymous):

I know a mole is 6.02 * 10^23 thats about it

OpenStudy (wolfe8):

That is the Avogadro number - the number of objects in 1 mole of substance. But I'm sorry I misread the question. You are already given the number of moles. So here, from our balanced equation N2 + 3H2 = 2NH3 we can see that 3 parts of H2 produces 2 parts of NH3. What do you think we will do to get the moles of NH3?

OpenStudy (anonymous):

Theres some formuala...

OpenStudy (wolfe8):

Nah. You have 24 mol which equals to 3 parts. Find for one part and multiple by 2 to get the mols of NH3

OpenStudy (anonymous):

Uhm...One part meaning?

OpenStudy (wolfe8):

One proportion by ratio

OpenStudy (anonymous):

Can you show me, I feel so lost...

OpenStudy (wolfe8):

Sure. So 24 mol is equal to 3 parts of H2 we use based on the equation so we divide 24 by 3. Then we know we get 2 parts of NH3 from the equation so we multiply it by 2

OpenStudy (wolfe8):

24/3*2 Get it? Want me to show it where there's whiteboard and mic?

OpenStudy (anonymous):

Yeah!

OpenStudy (anonymous):

so would it be 4 as the final answer?

OpenStudy (wolfe8):

Yeah. 4 mols. Do you understand what we did though?

OpenStudy (wolfe8):

NOOOOOO. 24/3 is 8 multiplied by 2 is 16

OpenStudy (anonymous):

You know there is 24 mol. In 3 equal parts oh H2 and 2 equal parts of NH3?

OpenStudy (anonymous):

Where do you get that information though? and oh okay just error in what comes first! sorry

OpenStudy (wolfe8):

Right. This is why we always need the balanced equation for stoichiometry.

OpenStudy (anonymous):

Can you show me on the whiteboard?

OpenStudy (wolfe8):

Sure. Can you make a meeting on twiddla.com ? I can't because I already made one. Sent the link to me in PM

OpenStudy (anonymous):

Actually its okay! i think i understood! Thanks so much for the help

OpenStudy (wolfe8):

Alright good job. Have a good night

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