Simplifying help please!!!!

Question

anonymous · Answer

30x^6 over 14y^5 times 7y^2 over 6x^4

tkhunny · Answer

Why not use the Laws of Exponents?

$\dfrac{x^{a}}{x^{b}} = x^{a-b}$

$x^{-c} = \dfrac{1}{x^{c}}$

Go!

anonymous · Answer

None of that showed up. Sorry. What is the law of exponents again

anonymous · Answer

Here's a better picture of the problem also

tkhunny · Answer

You should fix your browser, or use a better one.

(x^a)/(x^b) = x^(a-b)

anonymous · Answer

thanks. but how do use the law on this problem?

anonymous · Answer

cross cancel the variables.

anonymous · Answer

ok.

anonymous · Answer

you do that by subtracting the exponents right?

anonymous · Answer

the laws pertain on how you should deal with the exponents.  like x^6/x^4.  in this case you subtract the exponents.

anonymous · Answer

ok. so x would now be 2?

anonymous · Answer

or x^2?

anonymous · Answer

yep

anonymous · Answer

sometimes its easier to see the cancellations if you take it one step further and just multiply the fractions straight across.

anonymous · Answer

$$\frac{ 30x^6*7y^2 }{ 6x^4*14y^5 }$$

anonymous · Answer

ok so you go 30 x 6 and 7 by 14?

anonymous · Answer

yep reduce those.  move towards the bigger exponent.  either way it doesnt matter because y^-3 is the same thing as 1/y^3

anonymous · Answer

meaning to 6-4 and 5-2

anonymous · Answer

wouldn't it be a positive 3 then?

anonymous · Answer

yes, in the denominator.  which is the same as a negative 3 exponent in the numerator

anonymous · Answer

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