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Chemistry 21 Online
OpenStudy (anonymous):

Suppose CuS and O2 react to produce SO2, and a copper oxide which contains 88.82% copper by mass. Complete the reaction equation by entering the coefficients of the reactants and products and also the empirical formula of the copper oxide product. __CuS + __O2 -> __SO2 + __ ___

OpenStudy (wolfe8):

So wel know the copper is 88.82%, so the oxygen is...? Then, act as if those percentages are mass and find the number of moles.

OpenStudy (anonymous):

Oxygen would then be 11.18%, so..

OpenStudy (wolfe8):

So assume those are the mass in gram. Find the number of moles of each.

OpenStudy (anonymous):

There'd be 1.398 moles of copper, and 0.69875 moles of oxygen :)

OpenStudy (wolfe8):

Ok now, divide both by the smallest number of the two. So here it is 0.69875.

OpenStudy (anonymous):

Gotcha.

OpenStudy (anonymous):

I got about 2 for copper, and 1 for oxygen.

OpenStudy (anonymous):

So would Cu2O be the compound?

OpenStudy (wolfe8):

Yes. And then you can balance the equation.

OpenStudy (anonymous):

Alright. I'll see if my hw program takes it :)

OpenStudy (anonymous):

So I got 4CuS + 5O2 -> 4SO2 + 2Cu2O

OpenStudy (anonymous):

Yep, that worked! Thanks a lot! :D

OpenStudy (wolfe8):

Good job. You're welcome. Goodnight now. I think I'm going to bed.

OpenStudy (anonymous):

Good night! Thanks again! :)

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