Suppose CuS and O2 react to produce SO2, and a copper oxide which contains 88.82% copper by mass. Complete the reaction equation by entering the coefficients of the reactants and products and also the empirical formula of the copper oxide product. __CuS + __O2 -> __SO2 + __ ___
So wel know the copper is 88.82%, so the oxygen is...? Then, act as if those percentages are mass and find the number of moles.
Oxygen would then be 11.18%, so..
So assume those are the mass in gram. Find the number of moles of each.
There'd be 1.398 moles of copper, and 0.69875 moles of oxygen :)
Ok now, divide both by the smallest number of the two. So here it is 0.69875.
Gotcha.
I got about 2 for copper, and 1 for oxygen.
So would Cu2O be the compound?
Yes. And then you can balance the equation.
Alright. I'll see if my hw program takes it :)
So I got 4CuS + 5O2 -> 4SO2 + 2Cu2O
Yep, that worked! Thanks a lot! :D
Good job. You're welcome. Goodnight now. I think I'm going to bed.
Good night! Thanks again! :)
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