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Physics 18 Online
OpenStudy (anonymous):

Two balls launched at the same time with the same initial velocity/, the other theta (Θ) . Will the ball reach the ground at the same time? If not calculate the speed of each balls when they reach the ground. Determine the time of flight of each ball

OpenStudy (anonymous):

pls help @nincompoop

OpenStudy (anonymous):

pls help me @hba

OpenStudy (anonymous):

pls help me @thomaster

OpenStudy (anonymous):

pls help me @eliassaab

OpenStudy (anonymous):

pls me help @Jamierox4ev3r

OpenStudy (anonymous):

pls help me @ajprincess

OpenStudy (anonymous):

pls help @Albany_Goon

OpenStudy (anonymous):

pls help @QWERTYCraft

OpenStudy (anonymous):

pls help @primeralph

OpenStudy (primeralph):

Your question is faulty.

OpenStudy (primeralph):

Correct the errors in the question.

OpenStudy (anonymous):

Two balls launched at the same time with the same initial velocity. One was launched at an initial angle/, the other theta (Θ) . Will the ball reach the ground at the same time? If not calculate the speed of each balls when they reach the ground. Determine the time of flight of each ball. @primeralph

OpenStudy (primeralph):

"at an initial angle" ??? What follows that?

OpenStudy (anonymous):

it is the exact question.

OpenStudy (ajprincess):

0=u-gt_1 (at maximum height the final velocity is zero) u=gt_1 t_1=u/g-time taken to reach the maximum height by the first ball since the second ball is launched with an initial angle its velocity will have two components. horizontal and vertical. horizontal velocity will be ucosa and it will be constant through out the motion. 0=usina-gt_2 (at maximum height the final velocity is zero) t_2=usina/g-time taken to reach the maximum height by the second ball. the time taken to reach the ground is twice the time taken to reach the maximum height.

OpenStudy (anonymous):

Thanks @ajprincess

OpenStudy (ajprincess):

u r welcome:)

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