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Mathematics 16 Online
OpenStudy (anonymous):

algebera help @ganeshie8

OpenStudy (anonymous):

OpenStudy (anonymous):

@CGGURUMANJUNATH

OpenStudy (anonymous):

plss

OpenStudy (cggurumanjunath):

x^3/x^(1/12)

OpenStudy (cggurumanjunath):

x^a/x^b=x^(a-b)

OpenStudy (cggurumanjunath):

is it clear @plohrr ?

OpenStudy (cggurumanjunath):

x^3/x^(1/12)=x^(3-1/12)

OpenStudy (anonymous):

so x^3/x^(1/12) is the form it was in originally right

OpenStudy (cggurumanjunath):

yes

OpenStudy (anonymous):

ok and the second reply you posted is a formula?

OpenStudy (cggurumanjunath):

x^(3-1/12)=x^(36/12-1/12)

OpenStudy (cggurumanjunath):

yes

OpenStudy (cggurumanjunath):

3=36/12

OpenStudy (cggurumanjunath):

we are taking lcm .

OpenStudy (cggurumanjunath):

x^(3-1/12)=x^(36/12-1/12)=x^(35/12)

OpenStudy (anonymous):

ok wait too fast cx

OpenStudy (cggurumanjunath):

x^(35/12) is the final answer .

OpenStudy (cggurumanjunath):

ok.

OpenStudy (anonymous):

so the first step in simplifying is the sub it it in formula

OpenStudy (cggurumanjunath):

yes

OpenStudy (anonymous):

and what formula is that called.

OpenStudy (cggurumanjunath):

http://prntscr.com/2kyrc1

OpenStudy (cggurumanjunath):

go through the above link.

OpenStudy (cggurumanjunath):

it is the law of exponents.

OpenStudy (anonymous):

mmm i see

OpenStudy (anonymous):

and the next step is ?

OpenStudy (cggurumanjunath):

x^3/x^(1/12)=x^(3-1/12)

OpenStudy (anonymous):

what did you do there

OpenStudy (anonymous):

simplify ?

OpenStudy (cggurumanjunath):

yes

OpenStudy (cggurumanjunath):

i have used 3rd basic law of exponent .

OpenStudy (cggurumanjunath):

subtract exponents

OpenStudy (anonymous):

ohh ok

OpenStudy (anonymous):

x^(3-1/12)=x^(36/12-1/12) simplified is 3=36/12?

OpenStudy (cggurumanjunath):

x^3/x^(1/12)=x^(3-1/12) 3 and 1/12 u have to take lcm for subtracting these , u know how to take lcm right ? @plohrr

OpenStudy (cggurumanjunath):

3-1/12

OpenStudy (cggurumanjunath):

u know how to take lcm right ?

OpenStudy (anonymous):

yep

OpenStudy (cggurumanjunath):

very good.

OpenStudy (cggurumanjunath):

x^(3-1/12)=x^(36/12-1/12)=x^(35/12)

OpenStudy (cggurumanjunath):

x^(35/12) is the final answer .

OpenStudy (cggurumanjunath):

is it clear @plohrr ?

OpenStudy (anonymous):

yes ! thank you so much !!

OpenStudy (cggurumanjunath):

:)

OpenStudy (cggurumanjunath):

can u do the second part of the q .

OpenStudy (cggurumanjunath):

32 nd sqrt (x*x*x^5)

OpenStudy (cggurumanjunath):

use the first basic law of exponent here.

OpenStudy (cggurumanjunath):

http://prntscr.com/2kyrc1

OpenStudy (cggurumanjunath):

(x*x2*x^5) = (x^8)

OpenStudy (anonymous):

not really sure of that one

OpenStudy (cggurumanjunath):

32 nd sqrt (x*x2*x^5) =32 nd sqrt (x^8)

OpenStudy (cggurumanjunath):

is it clear or not @plohrr ?

OpenStudy (cggurumanjunath):

am i fast ? @plohrr

OpenStudy (anonymous):

yes its clear now

OpenStudy (cggurumanjunath):

32 nd sqrt (x^8) =(x^8)^(1/32)

OpenStudy (cggurumanjunath):

is it clear @plohrr ?

OpenStudy (cggurumanjunath):

32 nd sqrt (x^8) =(x^8)^(1/32)=(x^(8/32))

OpenStudy (cggurumanjunath):

32 nd sqrt (x^8) =(x^8)^(1/32)=(x^(8/32))=(x^(1/4))

OpenStudy (anonymous):

… so the simplified is x^(1/4))

OpenStudy (cggurumanjunath):

yes .

OpenStudy (cggurumanjunath):

they ( Megan and Julie ) started with expressions that are not equal

OpenStudy (anonymous):

so for the first: x^(35/12 and the second : (x^(1/4))

OpenStudy (cggurumanjunath):

that is the conclusion we draw from the given equation.

OpenStudy (cggurumanjunath):

yes

OpenStudy (cggurumanjunath):

both are not same right ? @plohrr

OpenStudy (anonymous):

yes thats true . and for the first we used the 3rd basic law of exponents. and for the second, we used the first?

OpenStudy (cggurumanjunath):

yes .

OpenStudy (anonymous):

:D can you help with some more

OpenStudy (cggurumanjunath):

sure . Always.

OpenStudy (anonymous):

ok hold on a sec

OpenStudy (cggurumanjunath):

ok.

OpenStudy (cggurumanjunath):

go ahead .

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