you mean the formula give you u =< , > and this problem give you u =< +...>
right?
OpenStudy (anonymous):
just pick i, k and + out, you have the form of the formula
OpenStudy (anonymous):
I mean u =<sqrt7, sqrt8>
v= <sqrt8, -sqrt 7>
problem is solvable
OpenStudy (anonymous):
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OpenStudy (anonymous):
You should do it by yourself. It's not hard. You have formula, just APPLY. Dat sit.
I can give you the answer in 1minute. But I wish you can handle it by YOURSELF
OpenStudy (anonymous):
i cant... bcoz im absent in that day... :(
OpenStudy (anonymous):
and i dont even know the title of that lesson...
OpenStudy (anonymous):
That is an unacceptable reason. You were absent, try to get the knowledge back is your duty.
OK, if you want to study, I can help. If you don't, It's perfectly OK to me.
OpenStudy (anonymous):
ok.... just tell me the formula and i will do the rest... and im absent bcoz of measles...
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OpenStudy (anonymous):
That was the past. Now, you are dealing with the problem you don't know how to solve. Be strong
cos (theta) =
OpenStudy (anonymous):
numerator: u dot v
denominator: magnitude of u * magnitude of v
I am sorry for inconvenience, the draw box doesn't work
OpenStudy (anonymous):
thanks for encouragement
OpenStudy (anonymous):
u dot v = < u1*v1 + u2 *v2>
OpenStudy (anonymous):
u =<u1, u2>
v = <v1,v2>
so, u dot v = ???
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OpenStudy (anonymous):
wait
OpenStudy (anonymous):
56i^2-56j^2 ?
OpenStudy (anonymous):
take i and j out, nothing to do with them here, you are correct , =??
OpenStudy (anonymous):
wait lets try this 1... this is easier
u = < –2, 9 > and v = < 3, –3 >
OpenStudy (anonymous):
one more thing , it is sqrt (56) -sqrt(56) =??
not 56 -56
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OpenStudy (anonymous):
no,no, just continue
OpenStudy (anonymous):
a -a =?
OpenStudy (anonymous):
0?
OpenStudy (anonymous):
you got the answer!!! check the option
u dot v = 0 (one of the option)
OpenStudy (anonymous):
yeah the 3rd one ^^ tnx :)
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OpenStudy (anonymous):
You see!! You CAN do it.
OpenStudy (anonymous):
u = < –2, 9 > and v = < 3, –3 > lets try this one :)
OpenStudy (anonymous):
ok, as usual, you have 2 parts
OpenStudy (anonymous):
cos (theta)=
numerator: u dot v
denominator: magnitude of u * magnitude of v
solve numerator first
OpenStudy (anonymous):
uhm... numerator is 33? am i right ?
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OpenStudy (anonymous):
-33, not 33
be careful with the sign
OpenStudy (anonymous):
huh? how come its -? <-2*-3> right ?
OpenStudy (anonymous):
no,not yet,
you still have denominator: magnitude of u * magnitude of v
u =<-2,9>
||u|| = sqrt((-2)^2 + 9^2)=?
OpenStudy (anonymous):
oh, sorry, your question is about numerator
OpenStudy (anonymous):
wait... we're still on numerator...
<-2*-3>+<9*3>
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OpenStudy (anonymous):
ok, I answer it now
u = <-2 , 9>
v = < 3, -3>
u dot v = < (-2) *3 + 9* (-3)>
= -6 - 27 = -33
now, put all of them into the formula of cos
\[cos (\theta )= \frac{u\dot v}{||u||*||v||=\frac{-33}{\sqrt{85}*\sqrt{18}}\]
use calculator to find out the answer
OpenStudy (anonymous):
-0.84?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
again, use calculator to find theta
by hitting cos^- of (-0.84)
OpenStudy (anonymous):
shift+cos?
OpenStudy (anonymous):
147.14?
OpenStudy (anonymous):
2nd + cos
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