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Mathematics 7 Online
OpenStudy (danielbarriosr1):

A metalworker has a metal alloy that is 20% cooper and another alloy that is 60% cooper. How many kilograms of each alloy should the metalworker combine to create 80kg of a 52% cooper alloy?

OpenStudy (anonymous):

Let x=the mass of 20% copper Let y=the mass of 60% copper x+y=80kg .20x+.60y=.52(80)% .20x+.60y=41.6% Substitute or use elimination to find the amounts needed of 20% copper alloy and the amount of 60% copper alloy to make 80kg of 52% copper alloy :)

OpenStudy (danielbarriosr1):

where did 80% came from?

OpenStudy (danielbarriosr1):

@amonaroll32

OpenStudy (anonymous):

It's .52(80)%, so 52% of 80 kg

OpenStudy (danielbarriosr1):

ok

OpenStudy (anonymous):

If you're stuck you can try to find y by subtracting 20% of the mass from the percentage. So basically (.20x+.60y=41.6)-.20(x+y=80)

OpenStudy (danielbarriosr1):

im just writing it

OpenStudy (anonymous):

Lol alright then, call me if you need any help :)

OpenStudy (danielbarriosr1):

Thanks

OpenStudy (anonymous):

Np

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