Question

Can someone help me with log problems? I'll give metal!

Answer 1

question?

Answer 2

Simplify 7 log3 k + 6 log3 m – 9 log3 n

Answer 3

uhh log 3k? all bases are 10?

Answer 4

a. 4 log3 km over n
b. 4 log3 (k + m – n)
c.log3 k to the seventh power m to the sixth power over n to the ninth power
d.log3 42 km over 9 n

Answer 5

log3 then comes k

Answer 6

c

Answer 7

is it the answer?

Answer 8

ill show u how!

Answer 9

I am not sure if it is or not. I have a couple more problems to do before I submit it but I will let you know and if it is will give you a medal I promise.

Answer 10

see that @lexipoo1998

Answer 11

Ok thank you! can you help me with a couple more?

Answer 12

um hafta go now im sorry ull find some one else!!
call any moderator hell help u

Answer 13

oh @ajprincess can u help him??

Answer 14

@.Sam. can u help him?
write the questions @lexipoo1998 .........

Answer 15

OK. Thanks again. @ajprincess do you think you can help?

Answer 16

post ur questions. I wil try my best to guide u towards the answer:)

Answer 17

Solve log11 (y + 8) + log11 4 = log11 60

Answer 18

I think these questions are using different bases just to develop the "concepts" multiply numbers add logs etc

Answer 19

log 11 (y+8) + log 11 4 = log 11 60
(y + 8)(4) = 60
4y + 32 = 60
y = (60 -32)/4

Answer 20

loga(b)+loga(c)-loga(d)
=loga(b)+loga(c)-loga(d)
=loga((b*c)/d)
loga(b)+loga(c)=loga(d)
loga(bc)=loga(d)
taking antilog both sides gives
bc=d
in your question
a=11
b=y+8
c=4
d=60
does that help?

Answer 21

So it would be 7. Ok. Thank you. I have one more and then that is it if you are up for it. I wish I could give you a medal but I already just a best answer :/

Answer 22

yes you got it

Answer 23

The number of milligrams of a drug that remains in a patient’s system after t hours is given by the function A(t) = Iert. Don was given 300 milligrams of medicine which leaves his bloodstream at a rate of 20%. How much of the medicine remains in his system after 4 hours?

Answer 24

That's the last one I need help with

Answer 25

the first one would be log3 k^7m^6/n^9

Answer 26

Ok Thanks. Can you help me with the word problem plese?

Answer 27

log base e to the power (rate)(time)
the rate -20% = -1/5 the time 4 hours

Answer 28

sorry it took so long to "translate" why A(t) = lert

Answer 29

about to check the ans
after 1 hr -20% of 300
after 2hrs -20% of previous balance etc

Answer 30

without logs my answer was 122.88
let me know if that is correct