If 8.65 grams of iron (III) oxide reacts with 7.85 grams of carbon monoxide to prduce 5.35 g of pure iron
fine the theoretical yield and percent yield
unbalanced equation: Fe2O3+Co-FeCO2

Question

If 8.65 grams of iron (III) oxide reacts with 7.85 grams of carbon monoxide to prduce 5.35 g of pure iron
fine the theoretical yield and percent yield
unbalanced equation: Fe2O3+Co->FeCO2

wolfe8 · Answer

First, balance the equation please. Then, find the number of mole of whatever info you have.

anonymous · Answer

Ok, but I don't really know how to do that

wolfe8 · Answer

Try this: https://www.khanacademy.org/science/mcat/physical-processes/stoichiometry/v/balancing-chemical-equations

joannablackwelder · Answer

The way the reaction is written it is impossible to balance. That is because the reaction is not written properly. The problem says that pure Fe is produced, so it should read Fe2O3 + CO -> Fe + CO2. Let me know if that works out better for you or if you have any other questions.