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calculus 2 - antiderivatives
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take integral the right hand side, what do you have?
5x^3 + 2x^2
+C
That is y(x) = 5x^3 +2x^2 +C now replace x = 0 y(0) = ??
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C
Oh sorry, your initial value is y(2) not y(0) redo, replace x =2 to get C , C =?
48
y(2) = 5*2^3+2*2^2 +C = 51 40 + 8 +C = 51 C = 51-48 = 3 Am I right?
yea
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so, at the end, you have y = 5x^3 +2x^2 +3 , just fill in the blanks to get credit
thank you
np
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