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Mathematics 16 Online
OpenStudy (anonymous):

calculus 2 - antiderivatives

OpenStudy (anonymous):

OpenStudy (loser66):

take integral the right hand side, what do you have?

OpenStudy (anonymous):

5x^3 + 2x^2

OpenStudy (loser66):

+C

OpenStudy (loser66):

That is y(x) = 5x^3 +2x^2 +C now replace x = 0 y(0) = ??

OpenStudy (anonymous):

C

OpenStudy (loser66):

Oh sorry, your initial value is y(2) not y(0) redo, replace x =2 to get C , C =?

OpenStudy (anonymous):

48

OpenStudy (loser66):

y(2) = 5*2^3+2*2^2 +C = 51 40 + 8 +C = 51 C = 51-48 = 3 Am I right?

OpenStudy (anonymous):

yea

OpenStudy (loser66):

so, at the end, you have y = 5x^3 +2x^2 +3 , just fill in the blanks to get credit

OpenStudy (anonymous):

thank you

OpenStudy (loser66):

np

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