Question

Need help Balancing equations!!

Balance the following reaction.

CS2 + Cl2 → CCl4 + S2Cl2


Balance the following reaction.

CH3OH + O2 → CO2 + H2O

Answer 1

Have no idea how to do this

Answer 2

CS2 + 3Cl2 -> CCl4 + S2CL2

Answer 3

CH3OH + O2 -> CO2 + 2H20

Answer 4

how did you solve that

Answer 5

both?

Answer 6

yes

Answer 7

For CS2 + Cl2 -> CCl4 + S2Cl2
First balance the number of Cl on both side
On the right there is a total of 6Cl so to balance that you need 3 Cl2 on the left to balance it.
Once that is done balance the C on the right there is 1 C and left also 1 C so it is balanced.
Since C is balanced now heck the S. Left has 2S and right also has 2S so it is balanced.

Answer 8

thanks your really good at this

Answer 9

I think i got the second one wrong hold on let me check

Answer 10

ok

Answer 11

the correct answer should be 2CH3OH + 3O2 -> 2CO2 + 4H20

Answer 12

how did you check it?

Answer 13

did you use a calculator?

Answer 14

First balance the H
Left has 4H so you need 2H20 to balance
After that the C is already balanced.
After that compare the O.
This is a bit tricky as you have left 3O but right 4O.
So to balance it you need one extra O.
So this is a little trick is you get 3/2 of O2.
Since halves are generally not pro looking we multiply to while equation by 2.
So we get from CH3OH + 3/2 O2 -> CO2 + 2H20
to 2CH3OH + 3 O2 -> 2CO2 + 4H20

Answer 15

no calculator required just simple math