What would be a possible formula for the exponential graph attached inside? y(x)=____________________ **not really sure what the format is for this :/ please explain? :)
graph! :)
You should have a general formula for it, or something. Otherwise there's too many possibilities of what you should start with. it could be y = a^(kx) or y = k*a^x or y = k*a^(bx)
oh okay.... so any of those work? :/ how do we choose which one to use?
You should be able to decide based on the chapter in the book, there should be a general exponential formula.
Because there's more than those...like y = k*a^(bx+c)
ermm for this chapter, I think the one we used was P=Poa^t but that's for population right? :/
or this one P=Poe^kt we went over both :/
Then use that. You have two points, plug them into the formula, and then you'll have to use both equations to find Po and a.
using the Poa^t formula?
yes
okay, so (-1,16) and (1,4) i forgot, how am i supposed to plug in though?
You plug them in by... plugging them in. P=Poa^t and you have points which will be (t, P)
oh okay.. so 16=Poa^-1 ? and 4=Poa^1 ?
yup , then solve for Po and a
how do i solve for Po and a? :/
how can you not know how to solve?
a^1 = a a^(-1) = 1/a that's it
ohh sorrry i forgot that Po can include the variable.. so you get Po= 16a? and Po=4 ?
if so, would the equations be y(x)=16a(1/a)^t ? and y(x)=4(1)^t ? :/ not sure.... i'm kinda confused on this :(
16= Po/a --> 16a = Po replace to the second one 4 = Po a
4 = 16a^2 --> a^2 = 1/4 --> a= 1/2
Yes/ No??
ohh okay so now we work towards making the equation with those values?
yes :)
still have Po. what is it? Po =?
4=Po(1/2)^1 4=Po(.5) 8=Po ?? :/
yup, plug back to get the whole answer, what is the equation of the line?
y(x)=8(1/2)^t ?
yup
or am i supposed to make the t be 1?
wait so just leave it as t ?
be x hehehe, not be t
y (x) = 8*(1/2)^x
don't trust me at detail. trust yourself.
ohh okay :) haha okay :) wait how come it becomes x instead of t?
is it because you're subbing the x value there?
"What would be a possible formula for the exponential graph attached inside? y(x)=____________________" that's why
because I inherit agent0smith stuff, he used t, so, I follow what he guide you
ohhh hahaha okie :) thanks you guys!! :)
because the graph shows x as the horizontal axis
ohh okay :) i'll have to make sure to remember that :) thank you for all your help!!! :)
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