Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

What would be a possible formula for the exponential graph attached inside? y(x)=____________________ **not really sure what the format is for this :/ please explain? :)

OpenStudy (anonymous):

graph! :)

OpenStudy (agent0smith):

You should have a general formula for it, or something. Otherwise there's too many possibilities of what you should start with. it could be y = a^(kx) or y = k*a^x or y = k*a^(bx)

OpenStudy (anonymous):

oh okay.... so any of those work? :/ how do we choose which one to use?

OpenStudy (agent0smith):

You should be able to decide based on the chapter in the book, there should be a general exponential formula.

OpenStudy (agent0smith):

Because there's more than those...like y = k*a^(bx+c)

OpenStudy (anonymous):

ermm for this chapter, I think the one we used was P=Poa^t but that's for population right? :/

OpenStudy (anonymous):

or this one P=Poe^kt we went over both :/

OpenStudy (agent0smith):

Then use that. You have two points, plug them into the formula, and then you'll have to use both equations to find Po and a.

OpenStudy (anonymous):

using the Poa^t formula?

OpenStudy (agent0smith):

yes

OpenStudy (anonymous):

okay, so (-1,16) and (1,4) i forgot, how am i supposed to plug in though?

OpenStudy (agent0smith):

You plug them in by... plugging them in. P=Poa^t and you have points which will be (t, P)

OpenStudy (anonymous):

oh okay.. so 16=Poa^-1 ? and 4=Poa^1 ?

OpenStudy (loser66):

yup , then solve for Po and a

OpenStudy (anonymous):

how do i solve for Po and a? :/

OpenStudy (loser66):

how can you not know how to solve?

OpenStudy (loser66):

a^1 = a a^(-1) = 1/a that's it

OpenStudy (anonymous):

ohh sorrry i forgot that Po can include the variable.. so you get Po= 16a? and Po=4 ?

OpenStudy (anonymous):

if so, would the equations be y(x)=16a(1/a)^t ? and y(x)=4(1)^t ? :/ not sure.... i'm kinda confused on this :(

OpenStudy (loser66):

16= Po/a --> 16a = Po replace to the second one 4 = Po a

OpenStudy (loser66):

4 = 16a^2 --> a^2 = 1/4 --> a= 1/2

OpenStudy (loser66):

Yes/ No??

OpenStudy (anonymous):

ohh okay so now we work towards making the equation with those values?

OpenStudy (anonymous):

yes :)

OpenStudy (loser66):

still have Po. what is it? Po =?

OpenStudy (anonymous):

4=Po(1/2)^1 4=Po(.5) 8=Po ?? :/

OpenStudy (loser66):

yup, plug back to get the whole answer, what is the equation of the line?

OpenStudy (anonymous):

y(x)=8(1/2)^t ?

OpenStudy (loser66):

yup

OpenStudy (anonymous):

or am i supposed to make the t be 1?

OpenStudy (anonymous):

wait so just leave it as t ?

OpenStudy (loser66):

be x hehehe, not be t

OpenStudy (loser66):

y (x) = 8*(1/2)^x

OpenStudy (loser66):

don't trust me at detail. trust yourself.

OpenStudy (anonymous):

ohh okay :) haha okay :) wait how come it becomes x instead of t?

OpenStudy (anonymous):

is it because you're subbing the x value there?

OpenStudy (agent0smith):

"What would be a possible formula for the exponential graph attached inside? y(x)=____________________" that's why

OpenStudy (loser66):

because I inherit agent0smith stuff, he used t, so, I follow what he guide you

OpenStudy (anonymous):

ohhh hahaha okie :) thanks you guys!! :)

OpenStudy (phi):

because the graph shows x as the horizontal axis

OpenStudy (anonymous):

ohh okay :) i'll have to make sure to remember that :) thank you for all your help!!! :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!