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In the reaction: H2SO4 + NaOH ==> Na2SO4 + H2O 29.33 g of NaOH is reacted with excess sulfuric acid to produce 9.041 g of water. What is the percent yield of the reaction? (Do not include units in the answer.)
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First balance the equation,
Then calculate the theoretical yield of water based on stoichiometry.
The 9.041g is the actual yield.
Percent yield is actual yield divided by theoretical yield * 100%
Alright! Thank you! :)
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