Need help to understand how to solve equations using Complete the Square for my test tomorrow. Ex: 4x2 – 8x – 5 = 0 **The 2 after the X is suppose to be x squared**
(2x+1)(2x-5)= 0 2x+1 = 0 & 2x -5 = 0. Solve for x.
Okay thank you. Can you help me understand how you got (2x+1)(2x-5)?
Okay no problem. Since the equation is 4x^2 - 8x - 5. You want to figure out what numbers multiply by each other to get four. There's 1, 2 & 4. 1 & 4 don't work because the numbers have to add up to the middle term, which is -8. & 1 & 5 are the only numbers you would multiply together to get 5. Since the last term is -5, you have to determine which number is going to have the subtraction sign.
I was told by my college algebra professor that "4" in 4x^2-8x-5 had to be 1 in order to solve it.
Oh, sorry. Then you would factor out the 4(x^2 - 2x +1) -5 - 4 = 0 4 (x^2 - 2x + 1) = 9
I believe that is where I am suck at. The farthest I've gone with the problem is x^2 - 2x + 1= 9
try my way 4x^2 = (2x)^2
8x = 2*2x 8*2 so, we need 4 to Complete the Square
(2x)^2 - 2 (2x)*2 +4 -4 -5 =0 (2x)^2-8x +4 -9 =0 (2x-2)^2 =9
so, there are 2 options: 2x -2 =3 ---> 2x =5 --> x = 5/2 2x-2 = -3 --> 2x = -1 --> x = -1/2
Wow, you lost me entirely. lol I can understand the answers to them. But how you got the answer is what I don't understand. I see the work you did, which is (2x)^2 - 2 (2x)*2 +4 -4 -5 =0 etc, but I'm not quite understanding it.
then, I am sorry.
Thank You though.
I think I can understand what the other person's strategy was. Where exactly are you lost?
I don't understand how we went from 4x^2-8x-5=0 to below:: (2x)^2 - 2 (2x)*2 +4 -4 -5 =0 (2x)^2-8x +4 -9 =0 (2x-2)^2 =9 I understand the answers Loser66 gave me and I know the answers is correct, but I want to learn how to solve this equation to get to the answer.
I think the way he did it was factor out 2's since 2*2 = 4 & 2*4 = 8. So (2x-2)(2x-2) = 4x^2 - 8x - 4. You can't forget the -5, so it becomes (2x)^2 - 8x + 4 - 9. If that makes sense.
Okay, I understand now and that does make sense, but where did the 9 come from?
Ok. I don't really get how completing the square helps u find the answer. But I can show u how to complete square for this problem
1. Add 5 to both sides 4x^2 -8x=5 2. Factor the 4 4(x^2 -2x)=5 3. Complete the square 4(x^2-2x+1)=5 4. U must balance the equation since u added 4 on the left side 4(x^2-2x+1)=5+4 So 4(x^2-2x+1)=9
The 9 was from adding the -5 & -4.
Then moving it to the other side of the equal sign.
Wait, u can solve by finding the square. U'll just be dealing with fractions. Check the last problem it's similar ro what u have to do for ur problem http://www.regentsprep.org/Regents/math/algtrig/ATE3/quadcompletesquare.htm
Thank you so much @itsonlycdeee and @nikato for helping me. Now, I understand how you guys got that far. I need to be able to Solve a quadratic equation using complete the square. Thank you @nikato I'll click the site.
No problem. I'm glad to have helped in some way
Ur welcome. And I'm sure that site will help u a lot
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