Question

Calculus 2 - Antiderivatives

Answer 1

80

Answer 2

for the first one?

Answer 3

yeah 80 ft/s

Answer 4

The initial speed is equal to the speed the ball would reach if dropped from 100 feet.

so I used the position function but not the one that uses meters, instead the one that uses ft, so 16t^2+v(t)+h

Same thing as last problem. So you find how long it takes to drop from 100 feet.

16t^2=100

then you use that t and plug it in to the velocity function

v(t) = 32(t)

Answer 5

so for the second question is 3200?

Answer 6

I got

Answer 7

168.75 ft is incorrect

Answer 8

let me think

Answer 9

Try 320ft

Answer 10

It was incorrect. that was my last try

Answer 11

you should tell me that you have x amount of tries lol

Answer 12

what was the answer?

Answer 13

answer was 640

Answer 14

oh so double that hmmm i wonder how they got that...

Answer 15

thanks though

Answer 16

yea I know how they got it now...do you want to know?

Answer 17

i used the vertex formula to get the time when it reaches the maximum height

-b/2a so -80/2(-2.5) = 16

plug in 16 into the position function

-2.5t^2+80t so -2.5(16)^2+80(16)=640