Find the Total Area of the regular pyramid? Picture: http://i626.photobucket.com/albums/tt350/nessie_black123/prob4.jpg
Can you find the area of the base?
How would i do that?
would it be 4 x 6??
You have one side on the base already given to you (6) and it is a regular shape, so you have six triangles making up the base. and they are all equilateral which means they have the same shape, and b * h /2 is the area of a triangle and both the b and h are 6.
please tell me if that doesn't make sense.
oh wait, not 4 x 6 i was looking at a different problem. wow. haha. so if both b and h are 6, do i just plug that in into b * h/2?
Yup and that would give you one triangle of the bottom, and there are six triangles...
so..18?
That would be one triangle on the bottom, and there are 6 triangles that make up the bottom of the shape.
so 6 * 18 would be for the entire base? 108?
Yup!
okay! so now what do i do with that in order to get the total area?
Now you need to get the hypotenuse of the 6 by 8 triangle in order to get the outside base to top length.
so would i use the Pythagorean theorem?
You are correct.
i got 10..
Me too, so now you need to do the same thing as in the first part to get the area of a single outside base to top triangle.
um, how would i do that. same equation?
Yup you still have b * h / 2 but now your b and h are different.
what would be the b and h though??
Do you have a picture? You are trying to find the outside-upper triangles.
this is the only picture i have..
Right, and you found the bottom area by a 6 by 6 triangle, and you found the hypotenuse going from the bottom edge to the top to be 10. So now you need the triangle that is formed from the hypotenuse and the bottom edge.
um.im sort of confused..what triangle?
You are trying to find the area of one of the six triangles that go from the base to the top.
oooh ok. so i use b*h/2 right? um..would it be 6*10/2??
Yup!
So then how many of those areas are there?
30. would i multiply that by 6?
Yeah, ad then add that to the bottom and you have your answer!
so 180 * 108?
oh wait you said add. so it would be 288?
Yup! :D
okay! But it says that the answer is ( sqrt + sqrt ) and that i need to fill it in..
uhm....
at the bottom of the picture, it shows the part that i have to fill in...
Is this an online class? and I see that now.
yeah. it's odyssey.
You can try 3*sqrt(36) + 18*sqrt(100) Or can you not do multiplication outside the sqrt signs?
i think that might work..it wont tell me if its right or not until i pass the entire lesson
sorry that answer would be wrong it should be 18*sqrt(36) + 18*sqrt(100)
okay thanks! could you help me with another one?
Sure, I only have another 30 mins though.
ok.
Okay so you have 2 different size triangles that you have to solve for can you tell me what the sides of each of the four triangles are?
um 12 and 10?
Right kind of, do you see that the regular pyramid can be broken up into four triangles?
yeah, like the faces?
Yup, now if you took all the faces apart, what would be each side length of each face?
..12?
or 10...haha idk!
Well there are four different triangles So one triangle would have side lengths of 12 by 12 by 12 do you see that one?
Yeah, on the bottom, right?
Right, now can try to find the side lengths of the other three triangles?
um, would they be 10,12, and 10?
Yup all three of the other ones would be that! So now we need to find the area's of them. We can start by the bottom one because that is easier.
ok, so would i just multiply 12 by 3?
That would be finding the perimeter. so no, lemmi think.
You need to use the formula B * H / 2 again, and you have the B but the height we would get by using the 30 60 90 method.
x / 2 * sqrt(3) would be the length of the height where x = 12 (the two non-base sides)
wat.
so 12/2*sqrt of 3 would be my height..?
Yup.
6 sqrt of 3?
Yup. which is about 10.39 but your answer needs square roots so you can leave it like that.
yeah, the thing at the bottom of the picture shows a square root.. so now what do i do?
Now you have to find the area of the three other squares (which are all the same) using the same method we used before.
would 10 be the height?
nope =/ I don't think I know the way that it should be done. I can give you two complicated formulas to do it... but that's probably not the way you are trying to be taught.
There are three triangle with 10, 10 and 12. and I am trying to figure out how to get the height from the 12(base) to the top.
ehhh. i just want to get this crap out of the way haha. as long as i can get it and understand it partially, its all good to me.
Well the complicated way is get the perimeter of the triangle divided by two so (10+10+12)/2 = 16
That is p and then you put it into this formula Area = sqrt(p(p-a)(p-b)(p-c)) p = 16, a = 10, b = 10, & c = 12
And if you do that it comes out to be 48
So now that you have the two different triangles can you tell me what the total area is? (sorry that the formula is complicated, I don't really know how to explain that I just know it works.)
uh. wat. hahahaha
The area to the triangle 10 by 10 by 12 is 48.... and I don't really know how to explain it except tell you that it is Heron's formula and here is a link http://www.mathopenref.com/heronsformula.html but if you understand the rest I think it would be good enough.
Did we ever get the area of the first 12, 12, 12 triangle?
ahhhh im so lost D:
wait okay, so we have 2 triangles. the 10 by 10 by 12 and the 12 by 12 by 12. the first one's area is 48. we still haven't found the second one. When we do, what do we do with these in order to find the total area. Add them together?
Well there are a total of 4 triangles, so we need to add 4 things together. Three of the triangles are the same size, but yes you add all four areas together.
right. so 48 stays the same but the other area of the 12 by 12 by 12 would be multiplied by 3?
We did get that the 12 by 12 by 12 triangle has a base of 12 and a height of 6*sqrt(3).
Nooo, =/ it's the other way around, If you look at the picture the three 10's are coming to a point, so the 10's are the ones multiplied by 3
ohhoh ok ok
So the area of the 10 by 10 by 12 is going to be 48 and the area of the 12 by 12 by 12 is going to be 12 * 6 * sqrt(3)
okay. so now what?
Now you have both area's that you need and know that the 10 by 10 by 12 area is multiplied by three and the other area is added to that.
and that is what you need to put into the assignment right?
so 144 + 72 sqrt of 3??
Yup!
NICE! it works! thanks so much! :DD
Your welcome :D!
Join our real-time social learning platform and learn together with your friends!