Determine if the function is even, odd or neither f(x)=x/(x2−1)
Replace x by -x, then simplify. 1) Is the resulting equal to the same function f(x)? (Then it is odd.) 2) Is the resulting function equal to its negative, \(f(x)=-\frac{x}{x^2-1}\)? (Then it is odd.) 3) If it satisfies neither of the two steps above, then the answer is neiter.
can you show me how this question is done @Jnlucero ??
Sure. :)
Thanks
f(-x) = (-x)/[(-x)^2-1]=-x/(x^2-1), since (-x)^2=x^2. Now notice that the resulting function equals its negative. That is, f(-x)=-f(x). Thus the function is odd. :) (PS: Why is the equation editor not working here?)
How about this ?? f(x)=x^6+8x^2
@Jnlucero
f(-x)=(-x)^6+8(-x)^2=x^6+8x^2 (the same function)
the one before this question, the function is odd but theres not (-) infront x^2
@Jnlucero is the last question odd??
f(-x)=(-x)^6+8(-x)^2=x^6+8x^2 (the same function)
2nd to last question: However, there is (-) in front of the whole expression x/(x^2-1)=f(x). Last question: It is the same function as f(x). So, it must be odd.
okay thanks
Last question, i mean its even.. (sorry. :/)
oh its fine
Thanks .:)
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