Question

Write the equation of the line that passes through (–4, 3) and is perpendicular to the line y= 7/5x-3/5

Answer 1

perpendicular lines have "flipped" values and their signs are changed. For example, if slope 1 = (2/3), a perpendicular slop would have to be (-3/2)

Answer 2

The slope in y= (7/5)x - (3/5) is (7/5). Which means it's perpendicular slope is...

Answer 3

-5/7

Answer 4

Yes

Answer 5

so how do i write it in standard form?

Answer 6

So now you use point-intercept form, using the point (-4,3) with slope (-5/7)

Answer 7

y-y1=m(x-x1), where -4 is x1, 3 is y1, and m=(-5/7)

Answer 8

Whats the equation for point intercept form?

Answer 9

y-3=(-5/7)(x+4)

Answer 10

y-(3)=(-5/7)(x-(-4))

y-3=(-5/7)x-(20/7) You distribute the (-5/7) to the x and the 4. Remember minus a negative makes it positive.


y-3=(-5/7)x-(20/7) solve for y

Answer 11

y-3=(-5/7)x-(20/7)
+3 +3

y=(-5/7)x+(1/7)

Answer 12

Now I'm going to check to make sure it is right

Answer 13

It's correct.