Question

Calculus 2 - Antiderivatives

Answer 1

Where is the question?

Answer 2

Definition : marginal cost = 'change in cost' with reference to 'change in quantity'

\(\large MC = \frac{dC}{dq}\)

q = quantity
C = cost
MC = marginal cost

Answer 3

the differential equation you want to solve wud be :
C'(q) = 9q^2 + 12q + 10

Answer 4

integrating both sides would give you the Cost function

Answer 5

3q^3+6q^2+10q

Answer 6

dont forget the constant

Answer 7

but thats for doing part b of the problem.

Answer 8

for part a, you just need to write the equation :o

Answer 9

so 3q^3+6q^2+10q for part a is correct?

Answer 10

for part a, its just 9q^2 + 12q + 10

Answer 11

you dont need to do anything. just enter that

Answer 12

thank you.

Answer 13

3q^3+6q^2+10q + C = 650 solve for C?

Answer 14

C is 650

Answer 15

oh so 3q^3+6q^2+10q + 650 is part B?

Answer 16

yess

Answer 17

thank you

Answer 18

np :)