Question

64y^2-x^3y^2=(64-x^3)

Answer 1

well if you are being asked to solve it... factor the left hand side...

the common factor is y^2... so what would it look like if you factored...?

Answer 2

y^2(64-x^3)
y^2(4^3-x^3)
The rest ?

Answer 3

yep... so your equation is

y^2(64 - x^3) = (64 - x^3)

so what do you do next....?

Answer 4

No clue what to do next

Answer 5

so are you being asked to solve the equation... or something else..?

Answer 6

Its asking me 64y^4-x^3y^4= ?
then it asks me if the polynomial is prime or not?

Answer 7

well it looks like they have divided by y^4 and left

64 - x^3

then, based in the information, its saying... can it be factored further...

if it can't be factored its prime

but

64 -x^3 can be factored to

(4 - x)(16 + 4x + x^2)

Answer 8

the question doesn't make a lot of sense to me... sorry

Answer 9

it's #7

Answer 10

@campbell_st

Answer 11

well the solution you have on the paper is correct

y^3(4 -x)(16 + 4x + x^2)

Answer 12

64 - x^3 is the difference of 2 cubes

as it becomes

4^3 - x^3

the standard form is

a^3 - b^3 = (a -b)(a^2 +ab + b^2)