how to solve for friction force if the ladder is 40deg with the horizontal surface.. and the ladder weighs 5ON. coefficient of friction is 0.2..

Question

vincent-lyon.fr · Answer

Use "Net force = 0" and "Net torque = 0"

anonymous · Answer

The normal force would be the mg and cos40. am i right?

vincent-lyon.fr · Answer

If there is no friction with the wall, the normal force at the foot of the ladder would be equal to mg, so that the vertical net force is zero.

anonymous · Answer

if theres a friction on the wall

vincent-lyon.fr · Answer

Use torque about top or bottom end of the ladder.

anonymous · Answer

the question really goes like this.. the bottom end of the ladder rest on a rough ground with 0.2 as coefficient that makes 65 w/ the horizontal. (ladder rest on a branch of a tree)